x-5x^(1/2)+4=0

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Solution for x-5x^(1/2)+4=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x-(5*x^(1/2))+4 = 0

x-5*x^(1/2)+4 = 0

t_1 = x^(1/2)

1*t_1^2-5*t_1^1+4 = 0

t_1^2-5*t_1+4 = 0

DELTA = (-5)^2-(1*4*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+5)/(1*2) or t_1 = (5-9^(1/2))/(1*2)

t_1 = 4 or t_1 = 1

t_1 = 1

x^(1/2)-1 = 0

1*x^(1/2) = 1 // : 1

x^(1/2) = 1

x^(1/2) = 1 // ^ 2

x = 1

t_1 = 4

x^(1/2)-4 = 0

1*x^(1/2) = 4 // : 1

x^(1/2) = 4

x^(1/2) = 4 // ^ 2

x = 16

x in { 1, 16 }

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